The mean and variance of the data 4,5,6,6,7,8,x,y where x<y are 6 and 94 respectively. The x4 + y2 is equal to

μ=36+x+y8=6 ⇒ x+y=12 σ2=226+x2+y28−36=94 ⇒x2+y2=80 So, x=4, y=8

The mean and variance of the data 4,5,6,6,7,8,x,y where x<y are 6 and 94 respectively. The x4 + y2 is equal to

μ=36+x+y8=6 ⇒ x+y=12 σ2=226+x2+y28−36=94 ⇒x2+y2=80 So, x=4, y=8

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The mean and variance of the data 4,5,6,6,7,8,x,y where x<y are 6 and $\frac{9}{4}$ respectively. The $x^{4} + y^{2}$ is equal to

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$μ = \frac{36 + x + y}{8} = 6 \Rightarrow x + y = 12 σ^{2} = \frac{226 + x^{2} + y^{2}}{8} - 36 = \frac{9}{4} \Rightarrow x^{2} + y^{2} = 80 S o, x = 4, y = 8$

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The mean and variance of the data 4,5,6,6,7,8,x,y where x<y are 6 and 94 respectively. The x4 + y2 is equal to

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The mean and variance of the data 4,5,6,6,7,8,x,y where x<y are 6 and $\frac{9}{4}$ respectively. The $x^{4} + y^{2}$ is equal to