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The mean deviation from means of the data 90,100,125,115,110 is__________

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10.4

10.6

10.8

answer is A.

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Detailed Solution

Mean $\bar{x} = \frac{90 + 100 + 125 + 115 + 110}{5}$

$\begin{array}{l} = \frac{540}{5} = 108 \\ M.D. = \frac{Σ | x_{i} - \bar{x} |}{m} = \frac{18 + 8 + 17 + 7 + 2}{5} \\ = \frac{52}{5} = 10.4 \end{array}$

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