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Q.

The mean free path of electrons in a metal is 4 x 10-8m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units of V/m

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a

8×107

b

8×10−11

c

5×10−11

d

5×107

answer is C.

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Detailed Solution

E=Vd=24×10−8

=0.5×108=5×107 Vm−1

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