The mean intensity of radiation on the surface of the Sun is about $10^{8} W / m^{2}$ . The rms value of the corresponding magnetic field is closest to:

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$10^{- 2} T$

$10^{2} T$

$10^{- 4} T$

$1 T$

answer is C.

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Detailed Solution

$Mean Intensity = \frac{B_{rms}^{2}}{μ_{0}} c \Rightarrow B_{rms}^{2} = \frac{10^{8} \times 4 π \times 10^{- 7}}{3 \times 10^{8}} \Rightarrow B_{rms} = 6.47 \times 10^{- 4} T$

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