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Q.

The mean time period of second’s pendulum is 2.00 s and mean absolute error in the time period is 0.05 s. To express maximum estimate of error, the time period should be written as

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a

(2.00±0.10) s

b

(2.00±0.01) s

c

(2.00±0.05) s

d

. (2.00+0.125) s

answer is C.

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Detailed Solution

Mean time period T = 2.00 s

Mean absolute error ΔT=0.05s

To express maximum estimate of error, the time period should be written as (2.00±0.05) s

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The mean time period of second’s pendulum is 2.00 s and mean absolute error in the time period is 0.05 s. To express maximum estimate of error, the time period should be written as