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The mean velocity of a particle performing S.H.M. with time period of 0.6s and amplitude of 10 cm averaged over a time interval during which it travels a distance of 5 cm, starting from extreme position is

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0.5 m/s

0.7 m/s

0.3m/s

1.04 m/s

answer is A.

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Detailed Solution

$\underset{average}{V} = \frac{\int_{0}^{T / 6} - a ω \sin ω t . d t}{\int_{0}^{T / 6} d t}$

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