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The measurement of the electron position is associated with an uncertainty in momentum, which is equal to ${1 × 10}^{-18} g - cm/s$ . The uncertainty in electron velocity is (mass of an electron is ${9 × 10}^{-28} g$ )

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${1 × 10}^{6} {cm s}^{-1}$

${1 × 10}^{11} {cm s}^{-1}$

${1 × 10}^{5} {cm/s}^{-1}$

${1 × 10}^{9} {cms}^{-1}$

answer is A.

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Detailed Solution

Given ,

${ΔP = 1 × 10}^{-8} {g cm s}^{-1}$

$(uncertainty in momentum)$

${Mass = 9 × 10}^{-28} g$

$ΔP = mΔv$

${1 × 10}^{-8} = 9 \times 10^{-28} × Δv (uncertainty in velocity)$

${Δv = 1 × 10}^{9} {cms}^{-1}$

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