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The median from the following data is
Mid - value Frequency
115
125
135
145
155
165
175
185
195
6
25
48
72
116
60
38
22
3

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153.79

165.93

153.91

165.18

answer is A.

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Detailed Solution

$C . I$	$f$	$C . f$
110-120	6	6
120-130	25	31
130-140	48	79
140-150	72	151
150-160	116	267
160-170	60	327
170-180	38	365
180-190	22	387
190-200	3	390

$N = \sum f_{i} = 390 \frac{N}{2} = \frac{390}{2} = 195$

Median $= l + (\frac{\frac{N}{2} - F}{f}) h$

$= 150 + (\frac{195 - 151}{116}) 10 = 150 + 3.79 = 153.79$

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