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The median of the following data is
Class interval Frequency
110 - 119 5
120 - 129 25
130 - 139 40
140 - 149 60
150 - 159 40
160 - 169 25
170 - 179 5

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144.5

154.5

134.5

140.5

answer is B.

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Detailed Solution

$C . I$	$f$	$C . f$
109-5	5	5
119.5	25	30
129.5	40	70
139.5	60	130
149.5	40	170
159.5	25	195
169.5	5	200

$N = \sum f_{i} = 200, \frac{N}{2} = \frac{200}{2} = 100 l = 1395, F = 70, f = 60, h = 10$

Median $= l + (\frac{\frac{N}{2} - F}{f}) h$

$= 139.5 + (\frac{100 - 70}{60}) 10 = 139.5 + 5 = 144.5$

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