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The median of trapezium $A B C D$ is 10cm and $A B = 8 cm$ , then $C D = (A B ∥ C D)$

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10 cm

13 cm

12 cm

15 cm

answer is C.

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Detailed Solution

Median $= 10 cm$

$A B = 8 cm, C D = ?$

We know that

$\frac{1}{2} (A B + C D) =$ Median of trapezium

$\begin{array}{l} \frac{1}{2} (8 + C D) = 10 \\ 8 + C D = 20 \\ C D = 20 - 8 \\ C D = 12 cm \end{array}$

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