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Q.

The melting point of a solid is 300 K and its latent heat of fusion is 600 cal mol-1. The entropy change for the fusion of 1 mole of the solid (in cal K-1 ) at the same temperature would be :

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a

200

b

2

c

0.2

d

20

answer is B.

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Detailed Solution

\Delta {S_{fusion}} = \frac{{\Delta {H_{fusion}}}}{T} = \frac{{600}}{{300}} = 2cal/K

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