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The metal salts formed during softening of hardwater using Clark's method are :

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$Ca {(OH)}_{2} and Mg {(OH)}_{2}$

${CaCO}_{3} and {MgCO}_{3}$

${CaCO}_{3} and Mg {(OH)}_{2}$

$Ca {(OH)}_{2} and {MgCO}_{3}$

answer is B.

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Detailed Solution

Clark's Method Reaction

$Ca {({HCO}_{3})}_{2} + C a {(OH)}_{2} \to 2 {CaCO}_{3} + 2 H_{2} O Mg {(H C O_{3})}_{2} + 2 Ca {(OH)}_{2} \to 2 {CaCO}_{3} + Mg {(OH)}_{2} + 2 H_{2} O$

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