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Q.

The metal which can form an oxide having metal : oxygen atoms ratio 2 : 3 is

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a

Bi

b

Na

c

Ba

d

Sn

answer is A.

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Detailed Solution

Assume that metal, M is there and charge on O is -2. 

Ratio of atoms in M and O is 2 : 3. This means that minimum value of O atoms is 3. Hence, charge on O atom is -6.

In Bismuth, Bi there are three valence electrons and for minimum value of Bi is 2 and valence electrons becomes +6. This nullify the charge of 3 O atoms, which is -6.

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