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The M.I. of a body is $1.2 kg m^{2}$ . Initially the body is at rest. In order to produce a rotational kinetic energy of 1500 J an angular acceleration of $25 rad s^{- 2}$ must be applied about the axis for a duration of

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Detailed Solution

KE = \frac{1}{2}

$1500 = \frac{1}{2} \times 1.2 \times ω^{2}$

$\frac{3000}{1.2} = ω^{2}$

$ω^{2} = 2500$

$ω = 50, ω_{0} = 0$

$\frac{ω - ω_{0}}{t} = α$

$\frac{50 - 0}{t} = 25$

$t = \frac{50}{25}$

$t = 2 \sec$

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