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Q.

The M.I of a uniform wire about Z - axis when it is placed with its mid point at the origin along X – axis is I. It is stretched to double its length and bent at the mid point. The two parts are placed along the X and Y - axis. The M.I about the Z - axis is

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a

2I

b

4I

c

$\frac{I}{2}$

d

$\frac{I}{6}$

answer is D.

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Detailed Solution

$I = \frac{{ML}^{2}}{12}; I^{1} = (\frac{M}{2}, \frac{L^{2}}{3}) \times 2 = \frac{{ML}^{2}}{3} = \frac{{ML}^{2}}{12} \times 4 = 4 I$

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