The middle term in the expansion of 4x3-154x8 is

n=8, Middle term =Tn2+1=T4+1 =C4 8 4x34 -154x4 =(70) 15x24

n=8, Middle term =Tn2+1=T4+1 =C4 8 4x34 -154x4 =(70) 15x24

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The middle term in the expansion of ${(4 x^{3} - \frac{15}{4 x})}^{8}$ is

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$70 {(15 x)}^{4}$

$1820^{8}$

$70 {(15 x^{2})}^{4}$

$2560 x^{4}$

answer is C.

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n=8, Middle term $= T_{\frac{n}{2} + 1} = T_{4 + 1}$

$= {}^{8}{C_{4}} {(4 x^{3})}^{4} {(\frac{- 15}{4 x})}^{4} = (70) {(15 x^{2})}^{4}$

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