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Q.

The minimum number of cells in mixed grouping required to produce a maximum current of 1.5 A through an external resistance of $30 Ω$ ,given the emf of each cell is 1.5 V and internal resistance is $1 Ω$ is

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a

120

b

60

c

40

d

30

answer is B.

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Detailed Solution

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$i_{max} = \frac{mE}{2 r} = \frac{nE}{2 R}$
n = number of cells in each row.
m = number of rows.
$\begin{array}{l} 1 .5 = \frac{1 .5 \times n}{2 \times 30} \\ n = 60 \\ 1 .5 = \frac{1 .5 \times m}{2 \times 1} \\ m = 2 \end{array}$
$∴$ total no of cells; = n x m = 2 x 60 = 120

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