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Q.

The minimum $p H$ required to prevent the precipitation of $Z n S$ in a solution containing 0.01 M $Z n C l_{2}$ and saturated with 0.10 M $H_{2} S$ is:
$(K_{s p} o f (Z n S) = 10^{- 21}, K_{a_{1}} \times K_{a_{2}} o f H_{2} S = 10^{- 20})$

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Detailed Solution

$K s p = [Z n^{2 +}] [S^{2 -}]$

$[S^{2 -}] = \frac{10^{- 21}}{10^{- 2}} = 10^{- 19}$

$K a_{1} \times K a_{2} = \frac{{[H^{+}]}^{2} [S^{2 -}]}{[H_{2} S]}$

$10^{- 20} = \frac{{[H^{+}]}^{2} \times 10^{- 19}}{0.1} [H^{+}] = 0.1 p H = 1$

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The minimum pH required to prevent the precipitation of ZnS in a solution containing 0.01 M ZnCl2 and saturated with 0.10 M H2S is:(Ksp of (ZnS)=10−21,Ka1×Ka2 of H2S=10−20)