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Q.

The minimum pressure required to compress 600 ${dm}^{3}$ of a gas at 1 bar to 150 ${dm}^{3}$ at 40°C is

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a

4.0 bar

b

0.2 bar

c

2.5 bar

d

1.0 bar

answer is B.

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Detailed Solution

As per Boyle's Law
$P_{1} V_{1} = P_{2} V_{2}$

$(1 bar) \times 600 {dm}^{3} = P_{2} \times (150 {dm}^{3}) P_{2} = 4 bar$

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