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Q.

The minimum value of $a \tan x + b \cot x$ equals the maximum value of $a \sin^{2} θ + b \cos^{2} θ$ where a>b>0 when

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a

a = b

b

a = 4b

c

a = 2b

answer is D.

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Detailed Solution

minimum of $a \tan x + b \cot x$ is $2 \sqrt{a b}$ & Maximum of $a \sin^{2} θ + b \cos^{2} θ$ is a $\Rightarrow 4 ab = a^{2} \Rightarrow a = 4 b$

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