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Q.

The minimum value of the function f(x)=02e|xt|dt  is

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a

2

b

2(e-1)

c

2e-1

d

e(e-1)

answer is B.

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Detailed Solution

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Forx>2f(x)=02extdtexet02 ex(1e2)Forx<0f(x)=02extdtexet02ex(e21)For0x2f(x)=0xextdt+x2etxdt=exet0x+exetx2=ex(ex1)+ex(e2ex)=1+ex+e2x1=e2x+ex2f(x)=ex(1e2)               x>2e2x+ex2       0x2ex(ex1)               x<0Forx>2f(x)min=e21For0x2f'(x)=e2x+ex=0ex=e2xe2x=e2x=1f(x)min=2e2=2(e1)

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