The minimum wavelength of x-rays produced by an electron acclerated through a potential difference of V volts is proportional to

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$\sqrt{V}$

$\frac{1}{V}$

$\frac{1}{\sqrt{V}}$

V²

answer is C.

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Detailed Solution

Kinetic energy of incident electrons is equal to maximum energy of X-rays generated.
$\begin{array}{l} \frac{1}{2} m_{e} v_{e}^{2} = e V = h v_{max} = \frac{h c}{λ_{min}} \\ λ_{min} = \frac{h c}{e V} \propto \frac{1}{V} \end{array}$

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