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The mixture containing the same number of molecules as that of 14 g of CO is

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14g of nitrogen + 8g of oxygen

7g of nitrogen + 8g of oxygen

14g of nitrogen + 16g of oxygen

7g of nitrogen + 16g of oxygen

answer is D.

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Detailed Solution

GMW of CO = 28g

28g of CO contain N_A molecules

14g of CO contain X molecules

$\large X = \frac{14}{28} \times N_A = \frac{N_A}{2}$

We know that GMW of any substance contain N_A molecules.

Thus 32g of O₂ (or) 28g of N₂ contain N_A molecules

1^st option

14g of Nitrogen + 16g of Oxygen

$Number\;of\;Molecules\;=\;\large \frac{N_A}{2} + \frac{N_A}{2} = N_A$

2^nd option

$\large number\;of\;molecules\;=\;\frac{N_A}{4} + \frac{N_A}{2} = \frac{3N_A}{4}$

3^rd option

14g of Nitrogen + 8g of Oxygen

$\large Number\;of\;molecules\;=\;\frac{N_A}{2} + \frac{N_A}{4} = \frac{3N_A}{4}$

4^th option

7g of Nitrogen + 8g of oxygen

$\large Number\;of\;molecules\;=\;\frac{N_A}{4} + \frac{N_A}{4} = \frac{N_A}{2}$

$\large \therefore$ 4^th option is correct

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