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Q.
The mixture that forms maximum boiling point azeotrope is
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a
Ethanol + Water
b
Water + Nitric acid
c
Acetone + Carbon disulphide
d
Heptane + Octane
answer is C.
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Detailed Solution
(I) CH3COCH3 + CS2
CH3COCH3 - CH3COCH3(A-A) ..... Dipole-Dipole attractions
CS2 - CS2 (B-B) ...... London dispersion forces
Addition of CS2 disturbs the Dipole-Dipole attractions between
acetone molecules
A-B interactions are weaker than A-A & B-B interactions
This mix. has higher V.P than expected from Raoult's law
It shows positive deviation
It is a minimum boiling azeotrope
(II) Heptane (A)+ Octane(B) , form an ideal sol.
Magnitude of A-B interactions are equal to A-A and B-B interactions
V.P of the mix. = PA+PB
It a perticular concentration both A & B boil at same temperature.
It is a constant boiling mix.
(III) Water (A) - HNO3(B)
HNO3 ionizes in water so A-B interactions are ion - dipole forces which are stronger
Than A-A (H-bonded forces) and B-B (H-bonded forces) interactions
This mix. has lesser VP than expected from Raoult's law
It shows -ve deviation
It is a maximum boiling azeotrope
(IV) C2H5OH(A) - H2O(B)
C2H5OH-C2H5OH ....... Inter molecular H-bonding
H2O-H2O ....... Inter molecular H-bonding
H2O-C2H5OH ....... Inter molecular H-bonding
Inter molecular H-bonding betweenC2H5OH - H2O
is weaker than inC2H5OH-C2H5OH and H2O-H2O
VP of C2H5OH - H2O is higher than expected
This Azeotropic mix. shows positive deviation from Raoult's law
VP is higher than expected its BP will be lesser than expected
BP of C2H5OH - H2O is lesser than that of any one of its components.
It is a minimum boiling azeotrpe