Q.

The mixture that forms maximum boiling point azeotrope is

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a

Ethanol + Water

b

Water + Nitric acid

c

Acetone + Carbon disulphide

d

Heptane + Octane

answer is C.

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Detailed Solution

(I) CH3COCH3 + CS2

CH3COCH3 - CH3COCH3(A-A) .....   Dipole-Dipole attractions

CS2 - CS2 (B-B)   ......    London dispersion forces

Addition of CS2 disturbs the Dipole-Dipole attractions between

acetone molecules

A-B interactions are weaker than A-A & B-B interactions

This mix. has higher V.P than expected from Raoult's law

It shows positive deviation

It is a minimum boiling azeotrope

(II) Heptane (A)+ Octane(B)  , form an ideal sol.

Magnitude of A-B interactions are equal to A-A and B-B interactions

V.P of the mix. = PA+PB

ΔHmix=0;  ΔVmix=0

It a perticular concentration both A & B boil at same temperature.

It is a constant boiling mix.

(III) Water (A) - HNO3(B)

HNO3 ionizes in water so A-B interactions are ion - dipole forces which are stronger

Than A-A (H-bonded forces) and B-B (H-bonded forces) interactions

This mix. has lesser VP than expected from Raoult's law

It shows -ve deviation

It is a maximum boiling azeotrope

(IV) C2H5OH(A) - H2O(B)

C2H5OH-C2H5OH ....... Inter molecular H-bonding

H2O-H2O .......   Inter molecular H-bonding

H2O-C2H5OH ....... Inter molecular H-bonding

Inter molecular H-bonding betweenC2H5OH - H2O

is weaker than inC2H5OH-C2H5OH and  H2O-H2O

VP of C2H5OH - H2O is higher than expected

This Azeotropic mix. shows positive deviation from Raoult's law

VP is higher than expected its BP will be lesser than expected

BP of C2H5OH - H2O is lesser than that of  any one of its components.

It is a minimum boiling azeotrpe

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