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The mode for the following frequency distribution is
C.I. 0-4 4-8 8-12 12-16
Frequency 4 8 5 6

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5.28

6.29

answer is D.

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Detailed Solution

$C . I$	$f$
0-4	4
4-8	8
8-12	5
12-16	6

the class 4-8 has Maximum frequency.

$l = 4, f_{0} = 4, f_{1} = 8, f_{2} = 5, h = 4$

Mode $= l + (\frac{f_{1} - f_{0}}{2 f_{1} - f_{0} - f_{2}}) h$

$= 4 + (\frac{4}{16 - 9}) \times 4 = 4 + \frac{16}{7} = 4 + 2.29 = 6.29$

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