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Q.

The modulus of $(3 - 4 i) (4 + 5 i)$ is

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a

$\sqrt{5} / \sqrt{41}$

b

$\sqrt{5} / 41$

c

$5 / \sqrt{41}$

d

$5 \sqrt{41}$

answer is A.

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Detailed Solution

$| (3 - 4 i) (4 + 5 i) | = | 3 - 4 i | | 4 + 5 i | = \sqrt{9 + 16} \cdot \sqrt{16 + 25} = 5 \sqrt{41}$

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