The molality of a sulfuric acid solution is 0.2. Calculate the total weight of the solution having 1000 gram of solvent. (Assuming density of water is 1 gram per m mL)

Molality (m) = number of moles of solute/weight of solvent in kg

Number of moles of solute $= molality\times weightofsolventinkg$$=0.2\times 1=0.2$

Mass of $H_{2}S{O}_4=0.2\times 98=19.6g$

Total mass of solution = mass of solute + mass of solvent

                                          =19.6 g + 1000 g = 1019.6 g