The molality of a sulfuric acid solution is 0.2. Calculate the total weight of the solution having 1000 gram of solvent. (Assuming density of water is 1 gram per m mL)

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1541

1000

1028

1019.6

answer is A.

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Detailed Solution

Molality (m) = number of moles of solute/weight of solvent in kg

Number of moles of solute $= m o l a l i t y \times w e i g h t o f s o l v e n t i n k g$ $= 0.2 \times 1 = 0.2$

Mass of $H_{2} S O_{4} = 0.2 \times 98 = 19.6 g$

Total mass of solution = mass of solute + mass of solvent

=19.6 g + 1000 g = 1019.6 g

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