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The molality of a $H_{2} O_{2}$ solution of density 1.068 gm/ml is 2 m. The only incorrect concentration of he same solution is:

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$6 .8 % (w / v)$

$6 .8 % (w / w)$

volume strength= 22.7 vol at STP

molarity = 2 M

answer is D.

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Detailed Solution

2 moles of $H_{2} O_{2}$ are present in 1000 gm of solvent.

$\begin{array}{l} M = 2 M \\ VS = 2 \times 11 .2 = 22 .4 \\ w / v % = \frac{68}{1000} \times 100 = 6 .8 % \\ w / w % = \frac{68}{1068} \times 100 = 6 .3 % \end{array}$

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