The molality of I L solution with x% H₂SO₄ is equal to 9. The weight of the solvent present in the solution is 910g. The value of x is:

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40.13

80.3

answer is B.

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Detailed Solution

$\begin{array}{l} Molality = \frac{1000 \times Weight of solute}{Mw \times Weight of solvent} \\ 9 = \frac{1000 \times W}{98 \times 910} \\ W = 802 .6 g L^{- 1} \\ = 80 .26 g per 100 mL \end{array}$

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