The molar conductance of NaCl, HCl and CH3COONa at infinite dilution are 126.45, 426.16 and 91.0 S cm2 mol-1 respectively. The molar conductance of CH3COOH at infinite dilution is. Choose the right option for your answer

λMCH3OOOH=λCH3COO−M+λNa+M+λH+M+λCr−M−λNa+M−λCrM=λCH3COONaM+λHClM−λNaClM= 91 + 426.16 - 126.45= 390.71Scm2mole-1

The molar conductance of NaCl, HCl and CH3COONa at infinite dilution are 126.45, 426.16 and 91.0 S cm2 mol-1 respectively. The molar conductance of CH3COOH at infinite dilution is. Choose the right option for your answer

λMCH3OOOH=λCH3COO−M+λNa+M+λH+M+λCr−M−λNa+M−λCrM=λCH3COONaM+λHClM−λNaClM= 91 + 426.16 - 126.45= 390.71Scm2mole-1

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The molar conductance of NaCl, HCl and CH₃COONa at infinite dilution are 126.45, 426.16 and 91.0 S cm²mol^-1 respectively. The molar conductance of CH₃COOH at infinite dilution is. Choose the right option for your answer

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540.48 S cm²mol^-1

390.71 S cm²mol^-1

698.28 S cm²mol^-1

201.28 S cm²mol^-1

answer is C.

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Detailed Solution

$\begin{array}{l} λ_{M}^{{CH}_{3} OOOH} = λ_{{CH}_{3} {COO}^{-}}^{M} + λ_{{Na}^{+}}^{M} + λ_{H^{+}}^{M} + λ_{{Cr}^{-}}^{M} - λ_{{Na}^{+}}^{M} - λ_{Cr}^{M} \\ = λ_{{CH}_{3} COONa}^{M} + λ_{HCl}^{M} - λ_{NaCl}^{M} \end{array}$
= 91 + 426.16 - 126.45
= 390.71Scm²mole^-1