The molar conductance of NaCl, HCl and $C H_{3} C O O N a$ at infinite dilution are 126.45, 426.16 and 91.0 S $c m^{2} m o l^{- 1}$ respectively. The molar conductance of $C H_{3} C O O H$ at infinite dilution is. Choose the right option for your answer.

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$540.48 S c m^{2} m o l^{- 1}$

$201.28 S c m^{2} m o l^{- 1}$

$390.71 S c m^{2} m o l^{- 1}$

$698.28 S c m^{2} m o l^{- 1}$

answer is C.

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Detailed Solution

$λ_{C H_{3} C O O H} = λ_{C H_{3} C O O N a} + λ_{H C l} - λ_{N a C l}$
$\begin{array}{l} = 426.16 + 91.0 - 126.45 \\ = 390.71 S c m^{2} m o l^{- 1} \end{array}$

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