The molar conductivities at infinite dilution of barium chloride, sulphuric acid and hydrochloric acid are 280, 860 and $426 S c m^{2} m o l^{- 1}$ respectively. The molar conductivity at infinite dilution of barium sulphate is ____ $S c m^{2} m o l^{- 1} .$ (Round off to the Nearest Integer)

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

answer is 288.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$\begin{array}{l} Λ_{m_{B a C l_{2}}}^{\circ} = 280 S c m^{2} m o l^{- 1} - - - (i) \\ Λ_{m_{H_{2} S O_{4}}}^{\circ} = 860 S c m^{2} m o l^{- 1} - - - (i i) \\ Λ_{m_{H C l_{}}}^{\circ} = 426 S c m^{2} m o l^{- 1} - - - (i i i) Λ_{m_{B a S O_{4}}}^{\circ} = ? \\ A d d e q u a t i o n (i) & (i i) a n d s u b t r a c t t w i c e o f e q u a t i o n (i i i), \\ Λ_{m_{B a S O_{4}}}^{\circ} = Λ_{_{B a^{2 +}}}^{\circ} + Λ_{_{S O_{4}^{2 -}}}^{\circ} = Λ_{m_{B a C l_{2}}}^{\circ} + Λ_{m_{H_{2} S O_{4}}}^{\circ} - 2 Λ_{_{H C l}}^{\circ} \\ = 280 + 860 - (426 x 2) = 288 S c m^{2} m o l^{- 1} \end{array}$