The molar conductivities at infinite dilution of barium chloride, sulphuric acid and hydrochloric acid are 280, 860 and $426 S c m^{2} m o l^{- 1}$ respectively. The molar conductivity at infinite dilution of barium sulphate is ____ $S c m^{2} m o l^{- 1} .$ (Round off to the Nearest Integer)

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

answer is 288.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$\begin{array}{l} Λ_{m_{B a C l_{2}}}^{\circ} = 280 S c m^{2} m o l^{- 1} - - - (i) \\ Λ_{m_{H_{2} S O_{4}}}^{\circ} = 860 S c m^{2} m o l^{- 1} - - - (i i) \\ Λ_{m_{H C l_{}}}^{\circ} = 426 S c m^{2} m o l^{- 1} - - - (i i i) Λ_{m_{B a S O_{4}}}^{\circ} = ? \\ A d d e q u a t i o n (i) & (i i) a n d s u b t r a c t t w i c e o f e q u a t i o n (i i i), \\ Λ_{m_{B a S O_{4}}}^{\circ} = Λ_{_{B a^{2 +}}}^{\circ} + Λ_{_{S O_{4}^{2 -}}}^{\circ} = Λ_{m_{B a C l_{2}}}^{\circ} + Λ_{m_{H_{2} S O_{4}}}^{\circ} - 2 Λ_{_{H C l}}^{\circ} \\ = 280 + 860 - (426 x 2) = 288 S c m^{2} m o l^{- 1} \end{array}$