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The molar conductivities $Λ_{KAc}^{0} and Λ_{HCl}^{0}$ at infinite dilution in water at 25°C are 91.0 S cm²/mol and 426.2 S cm²/mol respectively. To caculate $Λ_{HOAc}^{0}$ the additional value required is

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$Λ_{NaCl}^{0}$

$Λ_{H_{2} O}^{0}$

$Λ_{KCl}^{0}$

$Λ_{NaOH}^{0}$

answer is A.

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Detailed Solution

$Λ_{HOAC}^{0} = [Λ_{KOAC}^{0} + Λ_{HCl}^{0} - Λ_{KCl}^{0}]$

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