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The molar conductivities $\land_{NaOAc}^{0} and Λ_{HCl}^{0}$ at infinite dilution in water at 25⁰C and 91.0 and 426.2 S cm² / mol respectively. To caculate the additional value required is

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$\land_{NaCl}^{0}$

$Λ_{H_{2} O}^{0}$

$Λ_{KCl}^{0}$

$\land_{NaOH}^{0}$

answer is A.

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Detailed Solution

$λ_{{CH}_{3} COOH}^{0} = λ_{{CH}_{3} COONa}^{0} + λ_{HCl}^{0} - λ_{NaCl}^{0}$

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