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The molar conductivities $Λ_{NaOAc}^{\infty}$ and $Λ_{HCl}^{\infty}$ at infinite dilution in water at 25 °Care 910 and 426.2 S ${cm}^{2} {mol}^{- 1}$ ' respectively. To calculate, $Λ_{NOAc}^{\infty}$ the additional value required is

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$A_{NaOH}^{\infty}$

$Λ_{NaCl}^{\infty}$

$Λ_{KCl}^{\infty}$

$Λ_{H_{2} O}^{α}$

answer is A.

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Detailed Solution

We have $Λ_{HOAc}^{\infty} = Λ_{NaOAc}^{\infty} + Λ_{HCl}^{\infty} + Λ_{NaCl}^{\infty}$ Hence, in addition to $Λ^{\infty} (NaOAc)$ and $Λ^{\infty} (HCl)$ we must have the value of $Λ^{\infty} (NaCl)$

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