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The molar conductivities $Λ_{NaOAc}^{o}$ and $Λ_{HCl}^{o}$ at infinite dilution in water at $25^{o} C$ are 91.0 and 426.2 S ${cm}^{2} / mol$ respectively. To calculate $Λ_{{CH}_{3} COOH}^{o}$ , the additional value required is:

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$Λ_{H_{2} O}^{o}$

$Λ_{KCl}^{o}$

$Λ_{NaOH}^{o}$

$Λ_{NaCl}^{o}$

answer is D.

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Detailed Solution

According to Kohlrausch's law;

$Λ_{{CH}_{3} COOH}^{o} = Λ_{{CH}_{3} COONa}^{o} + Λ_{HCl}^{o} - Λ_{NaCl}^{o}$

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