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Q.

The molar conductivity of 0.007 M acetic acid is 20S $c m^{2} m o l^{- 1}$ . What is the dissociation constant of acetic acid? Choose the correct option. $[\begin{array}{l} \land_{H^{+}}^{0} = 350 S c m^{2} m o l^{- 1} \\ \land_{C H_{3} C O O^{-}}^{0} = 50 S c m^{2} m o l^{- 1} \end{array}]$

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a

$2.50 \times 10^{- 4} m o l L^{- 1}$

b

$1.75 \times 10^{- 4} m o l L^{- 1}$

c

$1.75 \times 10^{- 5} m o l L^{- 1}$

d

$2.50 \times 10^{- 5} m o l L^{- 1}$

answer is D.

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Detailed Solution

$\begin{array}{l} \land_{C H_{3} C O O H}^{0} = \land_{H^{+}}^{0} + \land_{C H_{3} C O O H}^{0} \\ = 350 + 50 = 400 \\ α = \frac{A_{c}}{\land^{0}} = \frac{20}{400} = 0.05 \\ α = \sqrt{K a C} o r K a = C α^{2} \\ K a = 7 \times 10^{- 3} \times 0.05 \times 0.05 \\ = 1.75 \times 10^{- 5} m o l L^{- 1} \end{array}$

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The molar conductivity of 0.007 M acetic acid is 20S cm2 mol−1 . What is the dissociation constant of acetic acid? Choose the correct option.∧H+0=350 S cm2 mol−1∧CH3COO−0=50 S cm2 mol−1