Q.

The molar conductivity of 0.007 M acetic acid is 20S cm2mol1  . What is the dissociation constant of acetic acid? Choose the correct option.H+0=350  Scm2mol1CH3COO0=50Scm2mol1

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a

2.50×104molL1

b

1.75×104molL1

c

1.75×105molL1

d

2.50×105molL1

answer is D.

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Detailed Solution

CH3COOH0=H+0+CH3COOH0                    =350+50=400α=Ac0=20400=0.05α=KaC  or  Ka=Cα2Ka=7×103×0.05×0.05       =1.75×105molL1

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