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Q.

The molar enthalpy of fusion of water is 6.01 kJ ${mol}^{- 1} .$ The entropy change of 1 mol of water at its melting point will be

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a

$109 J {mol}^{- 1} K^{- 1}$

b

$22 J {mol}^{- 1} K^{- 1}$

c

$44 J {mol}^{- 1} K^{- 1}$

d

$11 J {mol}^{- 1} K^{- 1}$

answer is A.

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Detailed Solution

$∆ S = \frac{6.01 \times 10^{3}}{(0 + 273)} J / mol = 22 J / mol$

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