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The molar heat capacity of water at constant pressure is $75 {JK}^{- 1} {mol}^{- 1}$ . When 1.0 kJ of heat is supplied to 100 g of temperature of water is

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2.4 K

6.8 K

4.8 K

1.2 K

answer is B.

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Detailed Solution

$\begin{array}{l} C = \frac{q}{T_{2} - T_{1}} \\ Q = mCΔT \\ 1000 = \frac{100}{18} \times 75 \times ΔT \\ ΔT = 2 .4 K \end{array}$

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