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The molar ratio of ${Fe}^{2 +}$ to ${Fe}^{3 +}$ in a mixture of ${FeSO}_{4}$ and ${Fe}_{2} {({SO}_{4})}_{3}$ having equal number of sulphate ions in both ferrous and ferric sulphates is:

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1:3

3:2

2:3

1:2

answer is B.

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Detailed Solution

$\begin{array}{l} 3 FeSO 4 \to 3 {Fe}^{+ 2} + 3 {SO}_{4}^{- 2} \\ {Fe}_{2} {({SO}_{4})}_{3} \to 2 {Fe}^{+ 3} + 3 {SO}_{4}^{- 2} \\ {Fe}^{+ 2} : {Fe}^{+ 3} = 3 : 2 \end{array}$

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