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The molar solubility of $P b I_{2}$ in 0.2M $P b {(N O_{3})}_{2}$ solution in terms of solubility product, $K_{s p}$

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${(K_{s p} / 0.2)}^{1 / 2}$

${(K_{s p} / 0.4)}^{1 / 2}$

${(K_{s p} / 0.8)}^{1 / 2}$

${(K_{s p} / 0.8)}^{1 / 3}$

answer is C.

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Detailed Solution

$[P b^{2 +}] {[2 I^{-}]}^{2} = K_{s p}$

$4 S^{2} (0.2) = K_{s p}$

$0.8 S^{2} = K_{s p}$

$S^{2} = \frac{K_{s p}}{0.8} (o r) {(\frac{K_{s p}}{0.8})}^{\frac{1}{2}}$

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