The molar solubility of Zn(OH)2 in 0.1M NaOH solution is X ×10-18M the value of 'x' is (Given the solubility product of Zn(OH)2 is 2 x 10-20)

Zn(OH)2→Zn+2S+2OH−SDue to common ion effect ∴Solubility product Ksp = (0.1)2 x 52 x 10-20 = 0.01 x 5S=2×10−200.01=2×10−18∴x=2

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The molar solubility of Zn(OH)₂ in 0.1M NaOH solution is $X \times 10^{- 18}$ M the value of 'x' is (Given the solubility product of Zn(OH)₂ is 2 x 10^-20)

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Detailed Solution

$Zn (OH)_{2} \to \underset{S}{{Zn}^{+ 2}} + \underset{S}{2 {OH}^{-}}$
Due to common ion effect
$∴$ Solubility product K_sp = (0.1)² x 5
2 x 10^-20 = 0.01 x 5
$S = \frac{2 \times 10^{- 20}}{0.01} = 2 \times 10^{- 18}$
$∴$ x=2

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