The molar solubility of Zn(OH)2 in 0.2M NaOH solution is y×10−19M. The value of y is ____(nearest integer) (Given: The solubility product of Zn(OH)2 is 2×10−20)

Ksp=[Zn2+][OH−]2 2×10−20=S(0.2)2=S×4×10−2S=12×10−18=0.5×10−18S=5×10−19M ∴x=5

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The molar solubility of $Z n {(O H)}_{2}$ in 0.2M NaOH solution is $y \times 10^{- 19} M .$ The value of y is ____(nearest integer) (Given: The solubility product of $Z n {(O H)}_{2}$ is $2 \times 10^{- 20}$ )

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answer is 5.

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Detailed Solution

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$K_{s p} = [Z n^{2 +}] {[O H^{-}]}^{2}$
$2 \times 10^{- 20} = S {(0.2)}^{2} = S \times 4 \times 10^{- 2}$
$S = \frac{1}{2} \times 10^{- 18} = 0.5 \times 10^{- 18}$
$S = 5 \times 10^{- 19} M$
$∴ x = 5$

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