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Q.

The molar solubility $(in m o l L^{- 1})$ of a sparingly soluble salt MX_{4 i}s s. The corresponding solubility product is $K_{sp}$ The solubility s is given in terms of $K_{sp}$ by the relation

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a

$s = {(K_{sp} / 128)}^{1 / 4}$

b

$s = {(128 K_{sp})}^{1 / 4}$

c

$s = {(256 K_{sp})}^{1 / 5}$

d

$s = {(K_{sp} / 256)}^{1 / 5}$

answer is D.

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Detailed Solution

We have ${MX}_{4} ⇌ M^{4 +} + 4 X^{-} s 4 s$

$K_{sp} = [M^{4 +}] {[X^{-}]}^{4} = (s) (4 s)^{4} = 256 s^{5}; Hence s = {(K_{sp} / 256)}^{1 / 5}$

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