The molarity and molality of a solution of sulphuric acid are 11.07 and 21.91 respectively. The density of the solution in g/ml is

The quantities provided in the question are Molarity of $H_{2}S{O}_4$ is 11.07 and Molality of $H_{2}S{O}_4$ 21.91.

We know that the molar mass of $H_{2}S{O}_4$ is equal to 98

So, the density of the solution can be mathematically calculated by using the formula:

$\mathrm{d}=\mathrm{molarity}\times (\frac{1}{\mathrm{molality}}+\frac{\mathrm{molar} \mathrm{mass} \mathrm{of} \mathrm{solute} \left({\mathrm{H}}_2{\mathrm{SO}}_4\right)}{1000})$

$=11.07\times (\frac{1}{21.91}+\frac{98}{1000})$

$=1.59$

Therefore the correct option is D) 1.59.