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The molarity of 9% (w/w) aqueous $H C l$ solution (density $1.11 g m L^{- 1}$ )

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2.50 M

3.25 M

2.73 M

1.52 M

answer is C.

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Detailed Solution

$M o l a r i t y (M) = \frac{w t . o f s o l u t e \times d e n s i t y o f s o l u t i o n \times 10}{m o l e c u l a r m a s s o f s o l u t e \times w t . o f s o l u t i o n} = \frac{10 \times 1.11 \times 9}{36.5} = 2.73$

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