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Q.

The molarity of a 70% (mass/mass) aqueous solution of a monobasic acid (X) is _______ M(Nearest integer)
[Given : Density of aqueous solution of (X) is 1.25 g mL^–1
Molar mass of the acid is 70 g mol^–1]

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answer is 125.

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Detailed Solution

Assuming 100 gm solution contain 70 gm solute.
Volume of 100 gm solution will be $\frac{100}{1.25}$ ml

$Molarity = \frac{70 / 70}{100 / 1.25} \times 1000 = 12.5 or 125 \times 10^{- 1}$

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