The molarity of a solution made by mixing 50ml of cone. $H_{2} {SO}_{4} (36 N)$ with 50 ml of water is

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36 M

18 M

9 M

6 M

answer is C.

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Detailed Solution

$\begin{array}{l} N_{1} V_{1} = N_{2} V_{2}, 36 \times 50 = N_{2} \times 100 \\ N_{2} = \frac{36 \times 50}{100} = 18; 18 N H_{2} S O_{4} = 9 M H_{2} S O_{4} . \end{array}$

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