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Q.

The molarity of concentrated sulphuric acid $(ρ = 1.834 g {cm}^{- 3})$ containing 95% of $H_{2} {SO}_{4}$ by mass is

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a

$17.78 M$

b

$8.88 M$

c

$13.32 M$

d

$4.44 M$

answer is D.

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Detailed Solution

Molarity $\frac{95 g / 98 g {mol}^{- 1}}{100 g / 1.834 g {cm}^{- 3}} = 0.01778 mol {cm}^{- 3} = 17.78 mol {dm}^{- 3}$

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