The molarity of the solution prepared by dissolving 6.3 g of oxalic acid $\left(H_2{C}_2{O}_4.2H_{2}O\right)$  in 250 mL of water in mol $L^{-1}$  is  $X\text{\hspace{0.17em} ×\hspace{0.17em}\hspace{0.17em}}{10}^{-2}$. The value of X is ………….( Nearest integer)   [Atomic mass: H:1.0,  C:12.0, O: 16.0].